Question

If p(1)=3 & p(x)= x^3-3x^2+4x+7k find the value of k

Answer 1

hope this help u........

Answer 2

$\textbf{Answer :}$

Given that,

p (x) = x³ - 3x² + 4x + 7k

Now,

p (1) = 3

or, 1³ - 3 (1²) + 4 (1) + 7k = 3

or, 1 - 3 (1) + 4 + 7k = 3

or, 1 - 3 + 4 + 7k = 3

or, 2 + 7k = 3

or, 7k = 3 - 2

or, 7k = 1

or, k = 1/7

Therefore, the value of k is 1/7

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