Question

If p+1, 3p and 3p+2 be any three consecutive terms of an AP, the value of P is

Answer 1

Answer:

=2/3

Solution:

ATQ,

p+1, 3p and 3p+2 are three consecutive terms of AP.

So the common difference in these should be same let the common difference be n.

Now,

3p-(p+1)=n __________equation 1

And also

(3p+2)-3p=n ___________equation 2

By combining equations 1 and 2 we get..

=3p-(p+1)=(3p+2)-3p

=3p-p-1=3p+2-3p

=2p-1=2

=2p=2+1

=2p=3

=p=2/3

Hope this helps you