If P + 1, 3P and 4P + 2 are in A.P. then P must be equal to :
(A) O
(B)2/3
(C)1/3
(D)3
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Answered by
0
Answer:
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Answered by
2
Answer:
Given:
p−1,p+3,3p−1 are in A.P.
∴2(p+3)=p−1+3p−1
⇒2p+6=4p−2
⇒2p=8
∴p=4
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