Question

If p=1 and q=-2 are roots of equation x^2-px+q =0, then quadratic equation will be

Answer 1

Answer:

The quadratic equation will be

x²-1x-2=0

Answer 2

If p = 1 and q = -2 are roots of equation , then quadratic equation will be $\bold{x^{2}-x-2=0}$.

Explanation:

We are to find the quadratic equation by putting the given values in the given equation. We have been given that p = 1 and q = -2 & $\mathrm{x}^{2}-\mathrm{p} \mathrm{x}+\mathrm{q}=0$

Replacing the given values p = 1 and q = -2 in the equation i.e. $\mathrm{x}^{2}-\mathrm{p} \mathrm{x}+\mathrm{q}=0$, we get

$\mathrm{x}^{2}-(1) \mathrm{x}+(-2)=0$

$x^{2}-x-2=0$ which is the required quadratic equation.

Hence, the quadratic equation is: $\bold{x^{2}-x-2=0}$.