Question

if p-1,p+1and3p-1are the three consecutive terms of an ap the p =​

Answer 1

If p-1, p+1, 3p-1 are three consecutive terms of an Arithmetic Progression, it's common difference must remain unchanged.

That is, T(2) - T(1) = T(3) - T(2)

(p+1) - (p-1) = (3p-1) - (p+1)

p+1 -p+1 = 3p-1 -p-1

1 + 1 = 2p -2

2 = 2p - 2

2p = 4

p = 4

Hence, the answer is p = 4.

Answer 2

Answer:

2

Step-by-step explanation:

Given p-1 , p+1 , 3p-1 are consecutive terms in AP

if three terms a,b,c are consecutive terms in AP then 2b= a+c

so,

     2(p+1) = p-1 + 3p-1

    2p+2 = 4p-2

    2p = 4

   p = 2

then terms are 1 ,3 ,5.