Question

 If p – 1, p + 3, 3p – 1 are in AP, then find the value of p​

Answer 1

Given:

(p−1) , (p+3) , (3p−1) are in A.P.

we know in a.p series 2b = (a + C)

∴2(p+3) = p−1+3p−1

⇒2p+6=4p−2

⇒2p=8

∴p=4

the value of p is 4