Question

If p – 1, p + 3, 3p – 1 are in AP, then find the value of p ​

Answer 1

Answer:

2 (p+3) = p−1+3p−1

2p + 6=4p−2

2p = 8

p = 4

Answer 2

Hey mate here is your answer ___

It is given that the following are in the Form of AP .

As we know that , D = a2 - a1

so here, a2 = P+3 and a1 = P - 1

now, a2 - a1 = d

=> (p+3) - (p-1) =d

=> p+3-p+1 =d

=> d = 4

Now, (3P-1)-(p+3) = 4

=> 3p-1-p-3 = 4

=>2P-4 = 4

=>2P = 8

=> p= 8/2

=>P= 4

•:The value of P is 4 .

I hope it helps you ....