Math, asked by sanjusaini30704, 6 months ago

if p–1,p+3,3p–1 are in ap , then find the value of p​

Answers

Answered by Anonymous
4

Answer:

The value of p is 4

Step-by-step explanation:

As these are in A. P. the common difference between them must be same

we know that d = a2-a1, a3-a2,......and so on

So, p+3-(p-1) =3p-1-(p+3)

p+3-p+1 = 3p-1-p-3

4 = 2p-4

4+4=2p

8=2p

p=8/2

p=4

Hope yoit helped you!

If it helped you then plz mark this as brainliest!

Answered by greeshmasaranya983
3

Answer:

p=4

Step-by-step explanation:

a=p-1

b=p+3

c=3p-1

if a,b,c are in AP then b=a+c/2

p+3=p-1+3p-1/2

p+3=4p-2/2

2p+6=4p-2

2p=8

p=8/2

p=4

I hope it's helpful for you

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