Question

if p-1, p+3, 3p-1, are in AP then find the value of p 4,-4,2,-2.​

Answer 1

Answer:

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Step-by-step explanation:

Now as we know that the p – 1, p + 3 and 3p – 1 are in AP.

And according to the condition of AP if the terms a, b and c are in AP then the difference of the two consecutive terms must be equal and is known as the common difference i.e. b – a = c – b = common difference of the AP.

So, now we can apply this condition in the given AP.

So, (p + 3) – (p – 1) = (3p – 1) – (p + 3) (1)

Now we had to solve the above equation to find the value of p.

So, opening the brackets in the above equation. We get,

p + 3 – p + 1 = 3p – 1 – p – 3

4 = 2p – 4

So, adding 4 to both the sides of the above equation. We get,

2p = 8

Dividing both sides of the above equation by 2. We get,

p = 4