Question

If p – 1, p + 3, 3p – 1 are in AP, then find the value of p.

Answer 1

Answer:

Given:

p−1,p+3,3p−1 are in A.P.

∴2(p+3)=p−1+3p−1

⇒2p+6=4p−2

⇒2p=8

∴p=4