Question

If P-1,p+3,3p-1 are in AP, then p is

Answer 1

p+3-(p-1)=3p-1-(p+3)

4=2p-4

2p=8

p=4

Answer 2

Answer:

p=4

Step-by-step explanation:

since they are in A.P

Therefore,

$a_{2} -a_{1} =a_{3} -a_{2}$

p+3-(p-1)=3p-1-(p+3)

p+3-p+1=3p-1-p-3

4=2p-4

4+4=2p

8=2p

8/2=p

4=p