Question

If (p – 1), (p – 3), (3p – 1) are in AP then p is equal to [1 thing it is (p-3) not (p+3)]​

Answer 1

Answer:

p=4

Step-by-step explanation:

Given:

p−1,p+3,3p−1  are in A.P.

∴2(p+3)=p−1+3p−1

⇒2p+6=4p−2

⇒2p=8

∴p=4