Question

If p-1, p+3, 3p-1 are in Ap then p is equal to

Answer 1

Answer:

P+3-(P-I) = 3P-1-(P+3)

4 = 2P-4

2P=8

P=4

Answer 2

Answer:

Step-by-step explanation:

p−1,p+3,3p−1  are in A.P.

∴2(p+3)=p−1+3p−1

⇒2p+6=4p−2

⇒2p=8

∴p=4