Question

If (p – 1), (p + 3) and 11 are in A.P., then find the value of ‘p’.​

Answer 1

Step-by-step explanation:

(p+3)-(p-1)=11-(p+3)

p+3-p+1=8-p

4=8-p

p=4

it is the correct answer

Answer 2

Given AP:

(p - 1), (p + 3), 11

To find:

The value of 'p'.

Solution:

(p - 1), (p + 3), 11 are in an AP according to the question.

Since these terms are in an AP, they have a common difference, i.e, the difference between the third and second term is equal to the difference between the second and the first term, and so on.

First term = a₁ = p - 1

Second term = a₂ = p + 3

Third term = a₃ = 11

➝ Second term - First term = Third term - Second term

➝ a₂ - a₁ = a₃ - a₂

➝ p + 3 - (p - 1) = 11 - (p + 3)

➝ p + 3 - p + 1 = 11 - p - 3

➝ 4 = 8 - p

➝ 4 - 8 = -p

➝ -4 = -p

The negative sign gets cancelled:

➝ p = 4

$\large{\boxed{\sf The \ value \ of \ 'p' \ is \ 4}}$

Read more about the concept used at:

https://brainly.in/question/29477995