Question

If p-1, p+3 and 3p-1 are in A.P then value of p will be:

(a) –1 (b) –2 (c) 1 (d) 2​

Answer 1

Answer:

p-1,p+3,3p-1 are in A.P.

so,

(p+3)-(p-1)=(3p-1)-(p+3)

=> p+3-p+1=3p-1-p-3

=> 4=2p-4

=> 2p=4+4=8

=> p=8/2=4

Answer 2

$\huge\red{ANSWER}$

$\impiles$ $\bold\purple {2 is correct answer}$

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