if p=1÷root(q+1),then what is dp÷dq
Anomi:
its dp/dq not dp÷dq
Answers
Answered by
3
dp/dq= –½.[{q+1}^–(3/2)]
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Answered by
1
dp÷dq =
–½/(q+1)(√q+1)
–½/(q+1)(√q+1)
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