Question

If p=1+route3 . Find the value of p2 + 1/p2.

In this p ke power 2 ha


Some1 plss...help fast ..

Answer 1

$(1 + \sqrt{3} ) ^{2} + 1 \div ( 1 + \sqrt{3} ) ^{2} = 4.25$
I think it is helpful to you.

Answer 2

Answer:

(10+3$\sqrt{3}$)/2

Step-by-step explanation:

$P^{2}$=$(1+\sqrt{3})^{2}$=1+$\sqrt{3}^{2}$+2$\sqrt{3}$

                    =1+3+2$\sqrt{3}$

                    =4+2$\sqrt{3}$

1/$P^{2}$=1/(4+2$\sqrt{3}$)

     ={1/(4+2$\sqrt{3}$)}*{(4-2$\sqrt{3}$)/(4-2$\sqrt{3}$)} (Rationalize)

     =(4-2$\sqrt{3}$)/{(4+2$\sqrt{3}$)*(4-2$\sqrt{3}$)}

     =(4-2$\sqrt{3}$)/{$4^{2}$-$(2\sqrt{3} )^{2}$}

     =(4-2$\sqrt{3}$)/{16-12}

     =(4-2$\sqrt{3}$)/4

$P^{2}$+1/$P^{2}$=(4+2$\sqrt{3}$)+(4-2$\sqrt{3}$)/4

            =(4+2$\sqrt{3}$)+(2-$\sqrt{3}$)/2

            =((8+4$\sqrt{3}$)+(2-$\sqrt{3}$))/2

            =(10+3$\sqrt{3}$)/2