Question

if (p+1)x +y =3 and 3y - (p-1)x=4 are perpendicular to each other , find the value of p.​

Answer 1

Answer:

The value of p is 2. If tho helps ... mark as brainliest please.

Step-by-step explanation:

From the first equation

(p+1)x + y = 3

make y the subject of the formula

y = -(p+1)x + 3

from equation of a straight line

y = mx + c

; m = -(p+1)............ 1

Second equation

3y - (p-1)x=4

make y the subject of the formula

3y = (p-1)x + 4

y = (p-1)x/3 + 4/3

comparing equation of a straight line

y = mx + c

m = (p-1)/3........... 2

since the two equations are perpendicular

m2 = -1/(m1)

$\frac{p - 1}{3} = \: \frac{ - 1}{ - (p + 1)} \\ cross \: multiplication \\ (p - 1)(p + 1) \: = \: 3 \: \: negative \: v \\ cancelled \: out. \\ by \: expansion.... \\ {p}^{2} - 1 = 3 \\ {p}^{2} = 4 \\ p = \sqrt{4} \\ p = 2$

Answer 2

Step-by-step explanation:

answer in pic .

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