Question

If (p+1)x+y =3 and 3y-(p-1)x=4 are perpendicular to each other find the value of p

Answer 1

Step-by-step explanation:

Since two lines are perpendicular to each other

i.e. X1*X2 + Y1*Y2=0

-(p+1)*(p-1)+ 3*1=0

-p^2+1+3=0

p^2=4

p = ± 2

Alternative method:

It can also be done by finding the slope of two lines m1, m2 separately and then multiply them to get the product = -1,

ie m1 m2= -1