If p=10^{m}, q=10^{n}, p^{n}*q^m =100 then prove mn=1
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k(k + 1). = n n + 1
We will prove this formula by induction. Base n = 1: It is shown above. ... We have 0 < q = (a − r)3 < a and by hypothesis we can write q = as3s .
.. It follows then that Sn has a prime divisor p. If p ≤ n, then p n!, and so p (n! ...
Indeed, we have b1 = 1, b2 = 0, n1 = 10, n2 = 3, M = n1n2 = 30, M1 = Mn1 = 3 and.
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