Math, asked by saveyouremotionkpb45, 23 days ago

If p = (1111... up to n digits), then what is the value of 9p2 + p ? + (a) 109 p (b) 2p. 10" (c) 109 p-1 (d) 109 p + 1

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Answered by 3458vanya

3

According to me the answer is (c)109 p-1

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