Question

if p =124. find the value of ^3√p(p^2+3p+3) + 1​

Answer 1

Answer:

∛124(15751)+1

Step-by-step explanation:

p= 124

∛p(p²+3p+3) + 1​ = ∛124(124²+372+3)+1

                           =∛124(15751)+1