If P(2,1), Q(-2,2) and R(-1,4) are the midpoints of sides Traingle ABC, find the vertices of triangle ABC.
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Answer:
Let P(1, 1),Q(2,−3), R(3, 4) be the mid-points of sides AB, BC and CA respectively of triangle ABC.
Let A(x
1
,y
1
),B(x
2
,y
2
) and C(x
3
,y
3
) be the vertices of triangle ABC.
Then, P is the mid point of AB
⇒
2
x
1
+x
2
=1,
2
y
1
+y
2
=1
⇒x
1
+x
2
=2andy
1
+y
2
=2 ..(1)
Q is the mid point of BC
⇒
2
x
2
+x
3
=2,
2
y
2
+y
3
=−3
⇒
2
x
2
+x
3
=4and
2
y
2
+y
3
=−3
⇒x
2
+x
3
=4andy
2
+y
3
=−6 ..(2)
R is the mid point of AC
⇒x
1
+x
3
=6andy
1
+y
3
=8 ..3)
From (1), (2) and (3) we get
(x
1
,y
1
)≡(2,8),(x
2
,y
2
)≡(0,−6)
and (x
3
,y
3
)≡(4,0)
Then the coordinates of the centroid
=(
3
x
1
+x
2
+x
3
,
3
y
1
+y
2
+y
3
)
=(
3
2+0+4
,
3
8−6+0
)=(2,
3
2
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