Question

if p(-2)=10 & p(x)= x^2-mx-6 find p(-3)​

Answer 1

Answer:

Given

x+2

x

3

+3x

2

−4

=x

2

−mx−2

Now x

3

+3x

2

−4 is divisible by x−2

So x−2 will be its one factor.

∴x

3

+3x

2

−4÷(x+2)

=x

3

+2x

2

+x

2

+2x−2x−4÷(x+2)

=x

2

(x+2)+x(x+2)−2(x+2)÷(x+2)

=(x+2)(x

2

+x−2)÷(x+2)

=x

2

+x−2

=x

2

−mx−2

∴ Comparing the coefficients,

m=−1

Answer 2

Step-by-step explanation:

$p( - 2) = 10 \\ p(x) = {x}^{2} - mx - 6 \\ Putting \:, x = - 2 \\ p( - 2) = 4 + 2m - 6 \\ 10 = 2m - 2 \\ m = 6 \\ \\ Hence \:, p(x) = {x}^{2} - 6x - 6 \\ p( - 3) = 9 + 18 - 6 \\ \: \: \: \: \: \: \: \: \: \: \: \: = 21 \\ \\ Hope \: it \: will \: help \: you \:$