If p=2-√3,q=√3-√7 and r=√7-√4, then find the value of p^3+q^3+r^3
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P+q+r=0
Then p^3 +q^3 +r^3 =3pqr
=3(2-v3)(v3-v7)(v7-2)
=3[4v7+3v3-8)
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