If P(2, 4), Q(0, 3), R(3, 6) and S(5, y) are the vertices of a parallelogram PQRS, then the value of y is
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7
Explanation:
P(2, 4), Q(0, 3), R(3, 6) and S(5, y) are the vertices of parallelogram PQRS
Join PR and QS which intersect O
O will be the mid point of PR and QS
when O is the mid point of PR the coordinate will be
(2+3/2, 4+6/2) = (5/2,5)
O is the mid point of QS
5= y+3/2 --> y+3=10
y = 10-3=7
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