Question

if p^2+4p+q^2+8q+r^2+10r=-45. then find the value of p+q-r​

Answer 1

Answer:

-1

Step-by-step explanation:

p²+4p+q²+8q+r²+10r = -45

p²+4p+q²+8q+r²+10r+45 = 0

(p²+4p+4)+(q²+8q+16)+(r²+10r+25) = 0

(p+2)²+(q+4)²+(r+5)² = 0.

Square numbers are always positive Wm

so when positive no. added and result is 0 then all of them are zero

p+2=0 => p=-2

q+4=0 =>. q= -4

r+5 = 0 => r = -5

p+q-r = (-2)+(-4)-(-5)

= -6+5 = -1