Math, asked by aryachandra1234, 1 year ago

if p=(2-√5)/(2+√5) and q=(2+√5)/(2-√5), find (p-q)

Answers

Answered by ShuchiRecites
28
Hello Mate!

p =  \frac{2  -   \sqrt{5}  }{2 +  \sqrt{5} }  \\  \frac{2 -  \sqrt{5} }{2 +  \sqrt{5} }  \times  \frac{2  - \sqrt{5} }{2 -  \sqrt{5} }  \\  =  \frac{4 + 5 - 4 \sqrt{5} }{4 - 5}  = 4 \sqrt{5}  - 9 \\  \\ q =  \frac{2 +  \sqrt{5} }{2 -  \sqrt{5} }  \\  =  \frac{2 +  \sqrt{5} }{2 -  \sqrt{5} }  \times  \frac{2 +  \sqrt{5} }{2 +  \sqrt{5} }  \\  =  \frac{4 + 5 + 4 \sqrt{5} }{4 - 5}  =  - 9 - 4 \sqrt{5}  \\  \\ p - q \\  = (4 \sqrt{5}  - 9) - ( - 9 - 4 \sqrt{5} ) \\  = 4 \sqrt{5}  - 9 + 9 + 4 \sqrt{5}  \\  = 8 \sqrt{5}

Have great future ahead!

ShuchiRecites: Thanks mate for taking dicision to attempt brainliesy
Answered by pgcpattoki27072001
9

p-q=(2-√5)/(2+√5) - (2+√5)/(2-√5)

    =2-√5  -  2+√5

      2+√5    2-√5



    =2-√5-2-√5

      (2²)-(√5)²


     =  -2√5  

          4-5



    = -2√5

       -1



   = +2√5 Answer

HOPE YOU UNDERSTAND.

plz mark as brainliest.

it tired me very much;)

plzzz


     



aryachandra1234: thank you for your time!!!! but that is not the correct answer so I couldn't mark as brainliest .... but anyway ..thank you..
pgcpattoki27072001: ok well
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