Math, asked by ashutosh2tiwari, 4 months ago

If P^2=a^2cos^2x+b^2sin^2x then prove that P+d^2P/dx=a^2b^2/P^3​

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Answered by diyabhana
0

Answer:

If p2 = a2cos2θ + b2sin2θ, then prove that p + d2p/dθ2 = a2b2/p3.

Answered by sayedzeenu
1

Step-by-step explanation:

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