Math, asked by ashutosh2tiwari, 5 months ago

If P^2=a^2cos^2x+b^2sin^2x then prove that P+d^2P/dx=a^2b^2/P^3

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Answered by diyabhana

0

Answer:

If p2 = a2cos2θ + b2sin2θ, then prove that p + d2p/dθ2 = a2b2/p3.

Answered by sayedzeenu

1

Step-by-step explanation:

I hope it will help you to understand

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