Question

if p=2-a, prove that a^3+6(ap)+p^3-8=0​

Answer 1

Answer:

Step-by-step explanation:

Given p=2−a

to prove a  

3

+6ap+p  

3

−8=0...(1)

Now put the value of P in eq (1)

a  

3

+6a(2−a)+(2−a)  

3

−8=0

⇒a  

3

+12a−6a  

2

+8−a  

3

−12a+6a  

2

−8=0

[∴(a−b)  

3

=a  

3

−b  

3

−3a  

2

b+3ab  

2

]

⇒0=0 (By eliminating equal terms we  

have LHS = RHS)

Answer 2

Step-by-step explanation:

refer to the attachment

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