Question

If p=2-a, prove that a^3+6ap-8= 0

Answer 1

Answer:

It is given that

p=2-a(1)

LHS =a*3+6ap+p*3-8

=a*3+6a (2-a) +(2-a)*3-8 from (1)

=a*3+12a-6a*2+2*3-3×2a*2+3×2a*2-a*3-8

=a*3+12a -6a*2+8-12a+6a*2-a*3-8

=0

RHS

mark as brainlist answer

follow me