Math, asked by Chakresh6251, 9 months ago

If p=2-a,prove that a^3+6ap -8=0

Answers

Answered by sayedsabana12
1

Answer:

if p=2-a

then,

a^3+6ap-8

=a^3+12a-6a^2-8

=a^3-3×a^2×2+3×2^2×a-2^3

=(a-2)^3

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