Question

if p=2-a prove that a^3+6ap+p^3-8=0​

Answer 1

Answer:

hola mate.

see the attachment

thanks

Answer 2

Answer:

proved

Step-by-step explanation:

It is given that ,

p = 2 - a -------( 1 )

LHS = a³ + 6ap + p³ - 8

= a³ + 6a( 2 - a ) + ( 2-a )³ - 8 [ from(1)]

= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8

= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8

= 0

= RHS

Hence proved.

Read more on Brainly.in - https://brainly.in/question/688452#readmore