Question

if p = 2-a , prove that a^3 + 6ap + p^3 - 8 = 0 ​

Answer 1

Step-by-step explanation:

Step-by-step explanation:a^3 + 6a×2-a + (2-a)^3 - 8 =0

Step-by-step explanation:a^3 + 6a×2-a + (2-a)^3 - 8 =0$remember \: \: \: \: \: \: \: \: \: \: \: p = 2 - a$

Step-by-step explanation:a^3 + 6a×2-a + (2-a)^3 - 8 =0$remember \: \: \: \: \: \: \: \: \: \: \: p = 2 - a$so

Answer 2

Answer:

using formula (a-b)^3