Question

if P = 2 - A prove that a ^3+6ap+p^3-8 =0​

Answer 1

$\boxed{Hey Mate Here Is Your Answer}$

$\red{Given}$

p = 2 - A --------------(1)

LHS is a^3 +6ap + p^3 - 8

so , a^3 +6a(2-A) +(2-A)^3 -8 .......[from Eq (1)]

=a^3 +12a -6a^2 +2^3 -3×2^2 a + 3×2a^2 -a^3 -8

=a^3 +12a -6a^2 +8 -12a +6a^2 -a^3 -8

=0

$\fbox{Hence Prove }$

$\bold{\huge{\fbox{\color{Maroon}{Hope It Helps You}}}}$