Math, asked by siddharthsinghr1810, 11 months ago

If P =2-a prove that a^3+ 6ap+ P - 8 = 0

Answers

Answered by unknownworld
1

Step-by-step explanation:

p(x)=a^3+6ap+P-8

put p=-2

a^3+6a(2-a)+2-a-8

a^3+12a-6a^2+2-a-8

a^3-6a^2-14a-6

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