Question

If P = 2 - a, prove that a2 + 6ap + p3 - 8 =0

Answer 1

Answer:

put the value of p in the equation

Step-by-step explanation:

then solve it

Answer 2

Answer:

Step-by-step explanation:

If p = 2 - a

Then, a² + 6a(2-a) + (2-a)³ - 8

Expanding the above equation

= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8

= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8

= 0

= RHS

Hence Proved