Question

If p = 2-a, prove that a3+6ap+p3

-8=0​

Answer 1

Answer:

given p= 2-a

to prove a3+6ap+p3-8=0=(1)

know put the value of p in eq(1)

a3+6a(2-a)+(2-a)3-8=0

Answer 2

Step-by-step explanation:

p=2-a. a³+6a(2-a)+(2-a)³-8. a³+12a-6a²+2³-a³-3×2×a(2-a)-8. a³+12a-6a²+8-a³-12a+6a³-8=0