If p^(2/a) = q^(2/b) = (p^b × q^a)^c
Show that abc = 1.
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1
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It is because there is no values are given
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hey there..
t. p/a^2 + q/b + r/c =1. …
a/p + b/q + c/r =0. ……. …. .(2)
Now squaring both sides of equation (1) , we get
[p/a + q/b + r/c]² = (1)²
=> (p/a)² + (q/b/b+1/2)² + (r/c+1/2^b)² + 2( pq/ab + qr/bc + pr/ac) = 1.
=> (p/a)² + (q/b)² +(r/c)² + 2[ pqr/abc ( c/r + a/p + b/q )] =1.
=> (p/a)² + (q/b)² + (r/c)² = 1. [ using equation (2)].
rest you can solve ..nilavra
nice to meet you..
#mark as the brainliest..
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