If p= 2 - a then prove that a^3+ 6ap + p^3-8 =0
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Substituting p=2-a
a^3+6a(2-a)+(2-a)^3-8
a^3+12a-6a^2+8-12a+6a^2-a^3-8
All terms cancel out.
Hence it is 0.
a^3+6a(2-a)+(2-a)^3-8
a^3+12a-6a^2+8-12a+6a^2-a^3-8
All terms cancel out.
Hence it is 0.
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