Math, asked by Prem143543, 1 year ago

if p=2-a, then prove that a^3+6ap+p^3-8=0

Answers

Answered by anuvanshchugh
5

Answer:


Step-by-step explanation:

Here is the answer





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Answered by vedantsharma750
3

Answer:2a^3


Step-by-step explanation:

a^3+6ap+p^3 -8

=a^3 + 6a(2-a) + (2-a)^3 -8

=a^3 + 12a - 6a^2 + 8 -a^3 - 12a +6a^2 -8

=0

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