if p=2-a, then prove that a^3+6ap+p^3-8=0
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Answer:2a^3
Step-by-step explanation:
a^3+6ap+p^3 -8
=a^3 + 6a(2-a) + (2-a)^3 -8
=a^3 + 12a - 6a^2 + 8 -a^3 - 12a +6a^2 -8
=0
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