Question

If p=(2−a), then the value of a2+6ap+p3−8, is ___.​

Answer 1

P = ( 2 - a )

a² + 6ap + (p)³ - 8. [ (a-b)³ = a³-b³-3ab

a² + 6a(2 - a) + (2 - a)³ - 8 (a-b) ]

a² + 12a - 6a² + (2)³- (a)³- 3(2)(a)(2 - a) - 8

a² + 12a - 6a² + 8 - a³ - 6a(2 - a) - 8

a² + 12a - 6a² + 8 - a³ - 12a + 6a² - 8

a² + 12a - 12a - 6a² + 6a² + 8 - 8 - a³

a² - a³