Math, asked by sheetaljoshi481, 11 months ago

If p=-2, q=-1 & r=3, find the value of p^3+q^3+r^3+ 3pqr​

Answers

Answered by parvaktrivedi
2

Answer: 18  

 

(-2)^3 +(-1)^3 +(3)^3 + 3(-2)(-1)(3)=-  8 - 1+9 +18=18

Answered by Sanskriticr7
4

Answer:

p= -1

q= -2

and, r= 3

-(1)^3+(-2)^3+(3)^3+3(-1)(-2)(3)

=>-1-8+27+18

=>36

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