Question

If p=-2,q=-1 and r = 3 find the value of p3+q3+r3+ 3 pqr

Answer 1

Hey there!

Given values,

p = -2

q = - 1

r = 3 .

Now,

p³ + q³ + r³ + 3 p q r

= ( -2)³ + ( - 1 )³ + ( 3)³ + 3 ( -2 ) ( -1 ) ( 3 )

= -8 + ( -1 ) + 27 + 3 ( 6 )

= -8 - 1 + 27 + 18

= 27 + 18 - 9

= 27 + 9

= 36 .

Therefore, The value of p³ + q³+r³ + 3pqr is 36

Answer 2

HEY THERE!!



Proper Question;-

If p=-2,q=-1 and r = 3 find the value of p³+q³+r³+ 3 pqr


Method of Solution;

Give;-

P=-2 , q=-1 ,r=3

Now, Considering on Question;

Substitute the value of P,q and r in Given Equation;

p³+q³+r³+3pqr

=> (-2)³+ (-1)³+ (3)³ +3.-2.-1.3

=> (-2×-2×-2) + (-1×-1×-1) + (3×3×3) +(3×6)

=> (4×-2) + (-1×1) + 27 +18

=> (-8) +(-1)+ 45

=> -8-1+45

=> -9+45

=> 36


Hence, Value of p³+q³+r³+3pqr = 36