Question

If p=-2,q=-1 and r = 3 find the value of p4+q4-r4

Answer 1

p⁴+q⁴-r⁴=(-2)⁴+(-1)⁴-(3⁴)

We know that (ab)^n=a^n×b^n

so,

(-1)⁴(2)⁴+(-1)⁴-(3)⁴

16+1-81. because (-1)^n=1 if n is even
And (-1)^n=-1. if n is odd.
17-81

-64

HOPE IT HELPS

Answer 2

$given.... \\ \: p = - 2 \\ q = - 1 \\ r = 3 \\ now \: we \: have \: to \: find \\ = p {}^{4} + {q}^{4} - {r}^{4} \\ = ( - 2) {}^{4} + { (- 1)}^{4} - (3 {}^{4} ) \\ = 16 + 1 - 81 \\ = 17 - 81 \\ = - 64 \\ hope \: this \: helps \: you$
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