Question

If P=(-2),Q=(-1) and R=3 then find the value of :-
2p²+q²-3r²​

Answer 1

Answer:

Here

p = - 2

q = - 1

r = - 3

${2p}^{2} + {q}^{2} - {3r}^{2} \\ = 2 {( - 2)}^{2} + {( - 1)}^{2} - 3 {(3)}^{2} \\ = 8 + 1 - 27 \\ = - 18$

Answer 2

Answer:

p = -2

Q = -1

R = 3

2p^3 + q^2 -3r^2

2 (-2)^3 + (-1)^2 - 3 (3)^2

-16 + 1 - 27

-15-27

-42