If p = 2, q = 1, r= -1, then the value of the following expression :
p²+q²+r²-pqr
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(fog)(x)=f(g(x))=2(3x+2)−1=6x+4−1=6x+3=3(2x+1)
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Answer:
p²+q²+r²-pqr
(2)²+(1)²+(-1)²- 2×1×-1
4+1+1-2×-1
6-(-2)
6+2
8
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