Question

If p = −2, q = −1, r = 3, find the value of 2p2 – q2 + 3r2​

Answer 1

Answer:

Step-by-step explanation:

2(4)-1+27=34

Answer 2

$= 2 {p}^{2} - {q}^{2} + 3 {r}^{2}$

$= 2( { - 2)}^{2} - ( { - 1)}^{2} + 3( {3)}^{2}$

$= 2(4) - 1(1) + 3(9)$

$= 8 - 1 + 12$

$= 8 + 11$

$= 19$