Question

If p= -2 q= -1 r=3, find the value of
$2p^{2} -q^{2} -q^{2} +3r^{2}$

Answer 1

Answer

32

Explanation

$2 \times ( - 2) {}^{2} - ( - 1) { }^{2} - (1) {}^{2} + 3 \times (3) {}^{2}$

$8 -1 - 1 + 27$

$32$

Answer 2

Given: p = -2, q = -1, r = 3
Substitute the value of p, q and r in the equation..

2p² - q² - q² + 3r²

= 2(-2)² - (-1)² - (-1)² + 3(3)²
= 8 - 1 - 1 + 27
= 35 - 2
= 33

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