Question

if p= -2 q=-1 r=3 then find 3p2q+5pq2+2pqr

Answer 1

Answer:

if p=-2 q=-1 and r=3

then

3(-2)2(-1)+5(-2*-1)+2(-2*-1*3)

-6*-2+5*-3+2*6

12+-15+12

24-15

9

Step-by-step explanation:

Answer 2

Answer:

p= -2 , q=-1 , r=3

3p2q + 5pq2 +2pqr  

=    (3×-2×2×-1) + (5×-2×-1×2) + (2×-2×-1×3)

= ( -6 ×-2 ) +(-10×-2) +(-4×-3)

=12+20+12

=44